2. Turunan pertama dari f(x)=x-4/3x+2 adalah
Jawaban:
1. 12
2. 11
3. akar (5/3), sekitar 1,29.
4. 1.5
5. -2/9
6. 7/16
7. 6x²-1
8.
[tex] \frac{14}{9 {x}^{2} + 12x + 4} [/tex]
9.
[tex] \frac{3}{5} {x}^{5} - \frac{5}{2} {x}^{2} + 12x + c[/tex]
10. -20 5/6= -125/6
Penjelasan dengan langkah-langkah:
1.
= (12+10+10+10+12+14+14+14)/8
= (96)/8
= 12.
2.
urutkan:
6, 7, 8, 9, 10, 12, 15, 19, 23, 31.
ada 10 data.
Median= (data ke-5+data ke-6)/2
= (10+12)/2
= 22/2
= 11
3.
Carilah rata-ratanya terlebih dahulu.
(5+3+5+4+6+7)/6
= 30/6
= 5
[tex] \sqrt{ \frac{\sqrt{ (3 - 5) {}^{2} + (4 - 5) {}^{2} + (5 - 5) {}^{2} + (5 - 5) {}^{2} + (6 - 5) {}^{2} + (7 - 2) {}^{2} } }{6} } \\ = \sqrt{ \frac{10}{6} } \\ = \sqrt{ \frac{5}{3} } [/tex]
sekitar 1,29
4.
Cari rata-rata:
(12+10+10+10+12+14+14+14)/8
= (96)/8
= 12
Sudah diketahui, kita bisa mencari:
[tex] \frac{ |10 - 12| + |10 - 12| + |10 - 12| + |12 - 12| + |12 - 12| + |14 - 12| + |14 - 12| + |14 - 12| } {8} \\ = \frac{2 + 2 + 2 + 0 + 0 + 2 + 2 + 2}{8} \\ = \frac{12}{8} = \frac{3}{2} \\ = 1.5[/tex]
5.
tidak akan menghasilkan bentuk tidak terdefeinisi, masukkan saja.
[tex] \frac{ {3}^{2} - 3 - 12}{ {3}^{3} } \\ = \frac{ - 6}{27} \\ = - \frac{2 }{9} [/tex]
6.
[tex] \frac{ {x}^{2} + x - 12 }{2 {x}^{2} - 32} \\ = \frac{(x + 4)(x - 3)}{2(x - 4)(x + 4)} \\ = \frac{x - 4}{2(x - 4)} \\ = \frac{ - 4 - 3}{2( - 4- 4)} \\ = \frac{ - 7}{ - 16} \\ = \frac{7}{16} [/tex]
7.
f(x)= 2x³-x-2
f'(x)= (2×3)x^(3-1)-1
f'(x)= 6x²-1
8.
= (u'v-uv')/v²
= ((x-4)'(3x+2)-(x-4)(3x+2)')/((3x+2))²
= ((3x+2)-(x-4)3)/(9x²+12x+4)
= ((3x+2)-(3x-12)/(9x²+12x+4)
= 14/(9x²+12x+4)
9.
[tex]\[ \int_{}^{} 3x^4 - 5x + 12 \,dx \] \\ = \frac{3}{4 + 1} {x}^{4 + 1} - \frac{5}{1 + 1} {x}^{1 + 1} + 12x + c \\ = \frac{3}{5} {x}^{5} + \frac{5}{2} {x}^{2} + 12x + c[/tex]
10.
[tex]\[ \int_{0}^{1} (2x + 5)(x - 4) \,dx \] \\ =\[ \int_{0}^{1} 2x^2 - 3x - 20 \,dx \] \\ = \frac{2}{3} {x}^{3} - \frac{3}{2} {x}^{2} - 20x \\ =( \frac{2}{3} ( {1}^{3} ) - \frac{3}{2} ( {1}^{2} ) - 20(1)) - \frac{2}{3} ( {0}^{3} ) - \frac{3}{2} ( {0}^{2} ) - 20(0) \\ = \frac{2}{3} - \frac{3}{2} - 20 - 0 \\ = - \frac{5}{6} - 20 - 0 \\ = - 20 \frac{5}{6} [/tex]
[answer.2.content]